1/4x^4+4x^2+16

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Solution for 1/4x^4+4x^2+16 equation: 


x in (-oo:+oo)

(1/4)*x^4+4*x^2+16 = 0

1/4*x^4+4*x^2+16 = 0

t_1 = x^2

1/4*t_1^2+4*t_1^1+16 = 0

1/4*t_1^2+4*t_1+16 = 0

DELTA = 4^2-(1/4*4*16)

DELTA = 0

t_1 = -4/(1/4*2)

t_1 = -8 or t_1 = -8

t_1 = -8

x^2+8 = 0

1*x^2 = -8 // : 1

x^2 = -8

t_1 = -8

x^2+8 = 0

1*x^2 = -8 // : 1

x^2 = -8

x belongs to the empty set

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